Corr...flip! Never thought I'd stepping into a classroom environment again after all these years
Figure 1: I would assume this would display a short circuit. Effectively, you've got a parallel circuit and (if memory serves me right back from school days) electricity flows down the path of least resistance. Since the load (lamp) offers resistance to the circuit, not enough current is running to the lamp to light it. Hence the diagram is technically incorrect
Figure 2: I'm gonna say that the ammeter's in the wrong place. If what I said in figure 1 is correct and electricity flows along the path of least resistance, it will flow through the ammeter instead of the lamp (a short circuit effectively). So, therefore the lamp will not light.
Figure 3: With a series circuit, which ever load is closest to the power source will take maximum voltage it requires in order to work. Whatever is left (as an analogy) will continue down the circuit and be used by whatever else is linked to the circuit. So, obviously, the first load has taken what it needs to work but has left minimal or no voltage required to power the other loads of the circuit. Hence why they won't light up
Well that was a blast from the past. If I don't score well, will I have to stay behind after school and do lines until I get it right
